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Volume in Conical Tank at t = 5 min

Dec 1, 2022

A photo of a whiteboard titled: Volume in Conical Tank at t = 5 min

We find the height of water in a conical tank such that:

$$ V = \frac{1}{3} \pi x^3 $$

given that water is flowing in at a rate $dV/dt = 1 m^3 / min$.

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